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Due: September 25th, 2020
Math 104 Assignment 4
Open sets are unions of balls
Show that if $U \subseteq M$ is an open set, then there is a set of balls whose union is $U$.
Interiors
Let $(M, d)$ be a metric space.
Recall that the interior of a subset $E \subseteq M$ is defined as \[E^{\intr} = \set{x \in M \mid \exists r \gt 0, B_r(x) \subseteq E}.\]
- Show that the interior of any set is open.
- Show that $E$ is open if and only if $E = E^\intr$.
- Prove that if $G \subseteq E$ is open, then $G \subseteq E^\intr$.
- Prove that the complement of the interior of $E$ is the closure of the complement of $E$. That is, show that \[\paren{E^\intr}^c = \overline{E^c}.\]
- Prove or provide a counterexample to the following claims:
- $\overline{E} = \overline{E^\intr}$.
- $E^{\intr} = \paren{\overline{E}}^\intr$.
Relatively open sets
Suppose that $(M, d)$ is a metric space, and $X \subseteq M$.
Recall that $X$ is therefore a metric space with metric inherited from $M$: for $x, y \in X$, we have $d_X(x, y) = d(x, y)$.
However, the open balls in $X$ are different from those in $M$.
We emphasize this by writing $B_r^X(x)$ or $B_r^M(x)$ to indicate where we are taking the ball.
Explicitly, if $x \in X$,
\[B_r^X(x) = \set{y \in X \mid d_X(x, y) \lt r}, \qquad\qquad\text{while}\qquad\qquad B_r^M(x) = \set{y \in M \mid d(x, y) \lt r}.\]
It also follows that we have different notions of "open" between $X$ and $M$: if $G \subseteq X$, we say $G$ is open relative to $X$ if for every $x \in G$ there is $r \gt 0$ so that $B_r^X(x) \subseteq G$.
- Show that if $U \subseteq M$ is open relative to $M$, then $U \cap X$ is open relative to $X$. (Hint: notice that for $x \in X$, $B_r^X(x) = B_r^M(x) \cap X$.)
- Show that if $G \subseteq X$ is open relative to $X$, then there is some $U \subseteq M$ open relative to $M$ so that $G = U \cap X$.
(Hint: use problem 1.)
- Give an explicit example of a metric space $M$ and sets $G \subseteq X \subseteq M$ so that $G$ is open relative to $X$ but not relative to $M$.
(Hint: take $X$ to be a subset of $M$ which is not open.)
- Suppose $K \subseteq X$. Prove that $K$ is compact relative to $X$ if and only if it is compact relative to $M$. (Hint: use parts A and B to convert open covers relative to $M$ to open covers relative to $X$ and vice versa.)
Limit points
- Determine the limit points of the set $S = \set{3-\frac3{m}\mid m \in \N} \cup [0,2] \subset \R$.
Let $(M, d)$ be a metric space, $E \subseteq M$, and $E'$ be the set of limit points of $E$.
- Show that $x \in E'$ if and only if every open set containing $x$ contains infinitely many elements of $E$.
- Prove that $x \in \overline{E}$ if and only if for every $r \gt 0$, $B_r(x) \cap E \neq \emptyset$.
Compact sets in the discrete metric
Let $M$ be a set, and $d$ the discrete metric on $M$, which is given by
\[d(x, y) = \begin{cases}0 & \text{ if } x = y \\ 1 & \text{ otherwise}\end{cases}.\]
Which subsets of $M$ are compact?
Here are some further problems to think about out of interest. You do not need to attempt them, nor should you submit them with the assignment.
Warm up
Determine if each of the following statements is true or false.
- Every unbounded subset of $\R$ is infinite.
- Every infinite subset of $\R$ is unbounded.
- If $E$ is a bounded subset of a metric space $X$, then every subset of $E$ is also bounded.
- If $E$ is an unbounded subset of a metric space $X$, then every subset of $E$ is also unbounded.
- $\Q$ is a dense subset of $\R$.
- $\R$ is a dense subset of $\C$, where $\C$ is given the metric $d(a+ib, x+iy) = \sqrt{(a-x)^2+(b-y)^2}$.
- If $E$ is a subset of $X$, then $(E^c)^c = E$.
- If $E$ is an open subset of a metric space $X$, then $E^c$ is closed.
- If $E$ is a subset of a metric space which is not open, then it is closed.
- If $(M, d)$ is a metric space, then $M$ is open.
- If $(M, d)$ is a metric space, then $M$ is closed.
- If $(M, d)$ is a metric space, then $M$ is bounded.
- If $(M, d)$ is a metric space, then $M$ is unbounded.
- If $E$ is a bounded subset of a metric space, then it is either open or closed.
- Any finite subset of a metric space is closed.
- Any finite subset of a metric space is open.
- Any finite subset of a metric space is compact.
- No finite non-empty subset of a metric space is closed.
- No finite non-empty subset of a metric space is open.
- No finite non-empty subset of a metric space is compact.
-
Limit points, II
Let $(M, d)$ be a metric space, $E \subseteq M$, and $E'$ be the set of limit points of $E$.
- Show by example that $E$ and $E'$ need not have the same limit points; that is, show that $E'$ and $(E')'$ may not be equal.
- Prove or provide a counterexample to the claim that $(E')' \subseteq E'$.
- Prove that $E'$ is closed.
-
Distances and compact sets
(This problem can be solved with what we know now, but will be easier with more tools at our command. It may show up on a later assignment.)
- Let $K$ be a non-empty compact subset of a metric space $(M, d)$.
For $x \in M$, define
\[d(x, K) = \inf\set{d(x, y) \mid y \in K}.\]
Show that there is a point $y\in K$ so that $d(x, K) = d(x, y)$.
Is this point unique?
-
Let $(M, d)$ be a metric space. Let $\mathscr{K} := \set{K \subseteq M \mid K \text{ is compact and non-empty}}$.
Define
\begin{align*}
d_H : \mathscr{K}\times\mathscr{K} &\to \R_{\geq 0} \\
(K, F) &\mapsto \max\paren{\sup\set{d(x, K) \mid x \in F}, \sup\set{d(y, F) \mid y \in K}}.
\end{align*}
Show that $(\mathscr{K}, d_H)$ is a metric space.
-
Nepo functions
Let us say that a function $f : M_1 \to M_2$ between metric spaces $(M_1, d_1)$ and $(M_2, d_2)$ is nepo if the preimage of every open subset of $M_2$ is open in $M_1$.
That is, if all sets of the form
\[f^{-1}(U) = \set{x \in M_1 \mid f(x) \in U}\]
where $U \subseteq M_2$ is open are themselves open, as subsets of $M_1$.
- Suppose that $K \subseteq M_1$ is compact and $f : M_1 \to M_2$ is nepo.
Show that $f(K) = \set{f(x) \mid x \in K} \subseteq M_2$ is compact.
Suppose that $M_1 \subseteq M_2$ and moreover that $d_1(x, y) = d_2(x, y)$ for all $x, y \in M_1$; that is, $M_1$ is a sub-metric space of $M_2$.
Show that the inclusion function $\iota : M_1 \to M_2$ given by $\iota(x) = x$ is nepo.
(Note that the metric space in which a set is considered is important here!
The goal is to show that open subsets of $M_2$ have preimages in $M_1$ which are open as subsets of $M_1$.
You may find it useful to first show that $\iota^{-1}(U) = U \cap M_2$.)
-
Compactness in the rational numbers
Let $S = \set{q \in \Q \mid q^2 \lt 2}$.
Show that $S$ is closed and bounded as a subset of the metric space $\Q$, but is not compact.
Is $S$ open in $\Q$?
(Hint: use problem 4, and the fact that $\sqrt2 \notin \Q$.)
Closures of balls versus closed balls
- Let $(M, d)$ be a metric space, $x\in M$, and $r \gt 0$.
Show that
\[\overline{B_r(x)} \subseteq \set{y \in M \mid d(x, y) \leq r}.\]
- Give an example to show that this inclusion may be proper. (Hint: consider $\Z$ as a metric space (although there are also many other examples).)
-
Open double covers
Let $(M, d)$ be a metric space.
Call a collection $\mathscr{U}$ of open sets an open double cover of $E \subseteq M$ if every point $x \in E$ is contained in at least two elements of $\mathscr{U}$.
-
Show that if $K \subseteq M$ is compact, then every open double cover of $K$ has a finite open double subcover. (That is, there is a finite subset of the original open double cover which remains an open double cover.)
-
Is it true that if $K \subseteq M$ is such that every open double cover has a finite open double subcover, then $K$ is compact?