We showed in lecture that if $\set{K_\alpha}$ is a collection of compact subsets of $M$ so that the interesction of every finite subcollection is non-empty, then the intersection of all the $K_\alpha$ is non-empty.
Recall that $d_1(\mathbf{x}, \mathbf y) = \abs{x_1-y_1}+\abs{x_2-y_2}$, $d_2(\mathbf{x}, \mathbf{y}) = \sqrt{\abs{x_1-y_1}^2 + \abs{x_2-y_2}^2}$, and $d_\infty(\mathbf x, \mathbf y) = \max(\abs{x_1-y_1}, \abs{x_2-y_2})$ are all metrics on $\R^2$.
Let $r \gt 0$ and $\mathbf x \in \R^2$.
(Note that there is no reason to find the best $s$ for a given $r$, just any one that works. It may be interesting to think about what the best is, though. Consider also what this says about drawing diamonds inside circles inside squares.)
Here are some further problems to think about out of interest. You do not need to attempt them, nor should you submit them with the assignment.
(Note that there is no reason to find the best $s \gt 0$ for a given $r$, just any one that works. It may be interesting to think about what the best is, though. Consider what this says about drawing diamonds inside circles inside squares.)
Let $(M, d)$ be a metric space, and suppose that $E \subseteq M$ is not bounded. Prove that $E$ has an infinite subset with no limit points in $M$. Use this to show that compact sets are bounded.
Note that this gives another way to prove that compact sets are bounded.