Let $(\mathcal{M}, d)$ be a metric space.
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Let $(x_n)_n$ be a sequence in $M$.
Then $(x_n)_n$ is convergent _____ it is bounded.
- if (but not only if)
- only if (but not necessarily if)
- if and only if
- (none of the above is true)
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If $(x_n)_n$ is a sequence in $E \subseteq M$ which converges, then $$L := \limni x_n \in \overline{E}.$$
Which of the following is a reasonable way to begin a proof of this fact?
- Let $n \in N$, and set $\epsilon = 2d(x_n, L)$.
- Let $\epsilon \gt 0$ and choose $N$ large enough that for $n \gt N$, $d(x_n, L) \lt \epsilon$.
- Suppose that $L \notin \overline{E}$, and choose $\epsilon \gt 0$ so that $\epsilon \lt d(L, x_n)$.
- Let $y \notin \overline{E}$ and let $r = d(y, L) \gt 0$.
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If $(x_n)_n$ is a sequence which takes on only finitely many distinct values, it converges.
- True.
- False.
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If $(x_n)_n$ and $(y_n)_n$ are convergent sequences with $$\limni x_n = a = \limni y_n,$$ then $\limni d(x_n, y_n) = 0$.
Which of the following inequalitities is true and would be useful in proving this fact?
- $d(x_n, a) \leq d(x_n, y_n) + d(y_n, a)$
- $d(x_n, y_n) - d(a, a) \leq \min(d(x_n, a), d(y_n, a))$
- $d(x_n, y_n) \leq d(x_n, a) + d(a, y_n)$
- $d(x_n + y_n, 2a) \leq d(x_n, a) + d(y_n, a)$